In the above reaction,the major product 'P' i | vedclass

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(A) The reaction involves the participation of the phenyl ring in a Neighboring Group Participation $(NGP)$ mechanism.$1$. The $\pi$-electrons of the

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(A) The reaction involves the participation of the phenyl ring in a Neighboring Group Participation $(NGP)$ mechanism.$1$. The $\pi$-electrons of the phenyl ring assist in the departure of the leaving group $(Br^{-})$.$2$. This leads to the formation of a phenonium ion intermediate.$3$. The nucleophile $(CN^{-})$ then attacks the more electrophilic carbon of the phenonium ion.$4$. This process results in the substitution of the $Br$ atom by the $CN$ group,leading to the product shown in option $A$.

In the above reaction,the major product '$P$' is:

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