CH_3-CH=CH_2 + NOCl rightarrow PIdentify the | vedclass

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(A) The reaction of $NOCl$ with an alkene follows Markovnikov's rule.$NOCl$ dissociates as $NO^{+}$ and $Cl^{-}$.The electrophile $NO^{+}$ attacks the

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$CH_3-CH(Cl)-CH_2(NO)$

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(A) The reaction of $NOCl$ with an alkene follows Markovnikov's rule.$NOCl$ dissociates as $NO^{+}$ and $Cl^{-}$.The electrophile $NO^{+}$ attacks the carbon atom with more hydrogen atoms (the terminal $CH_2$ group) to form a more stable carbocation intermediate.The nucleophile $Cl^{-}$ then attacks the more substituted carbon atom ($CH$ group).Thus,the product $P$ is $CH_3-CH(Cl)-CH_2(NO)$.

$CH_3-CH=CH_2 + NOCl \rightarrow P$
Identify the adduct.

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$CH_3-CH=CH_2 + NOCl \rightarrow P$Identify the adduct.