STATEMENT-1: Glucose gives a reddish-brown pr | vedclass

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(C) $Statement-1$ is True: Glucose is a reducing sugar and reacts with Fehling's solution to form a reddish-brown precipitate of cuprous oxide $(Cu_2O

Vedclass · Accepted Answer

$Statement-1$ is True,$Statement-2$ is False

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(C) $Statement-1$ is True: Glucose is a reducing sugar and reacts with Fehling's solution to form a reddish-brown precipitate of cuprous oxide $(Cu_2O)$.$Statement-2$ is False: The reaction of glucose with Fehling's solution produces gluconic acid and cuprous oxide $(Cu_2O)$,not cupric oxide $(CuO)$.The chemical reaction is:$C_6H_{12}O_6 + 2Cu^{2+} + 5OH^- \longrightarrow C_6H_{11}O_7^- + Cu_2O \downarrow + 3H_2O$

$STATEMENT-1$: Glucose gives a reddish-brown precipitate with Fehling's solution. because
$STATEMENT-2$: Reaction of glucose with Fehling's solution gives $CuO$ and gluconic acid.

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$STATEMENT-1$: Glucose gives a reddish-brown precipitate with Fehling's solution. because$STATEMENT-2$: Reaction of glucose with Fehling's solution gives $CuO$ and gluconic acid.