STATEMENT-1: The geometrical isomers of the c | vedclass

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(A) The complex $[M(NH_3)_4Cl_2]$ exhibits two geometrical isomers: $cis$ and $trans$.In the $trans$-isomer,the two $Cl$ atoms are at $180^{\circ}$ to

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$STATEMENT-1$ is True,$STATEMENT-2$ is True; $STATEMENT-2$ is the correct explanation for $STATEMENT-1$

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(A) The complex $[M(NH_3)_4Cl_2]$ exhibits two geometrical isomers: $cis$ and $trans$.In the $trans$-isomer,the two $Cl$ atoms are at $180^{\circ}$ to each other,and the molecule possesses a plane of symmetry.In the $cis$-isomer,the two $Cl$ atoms are at $90^{\circ}$ to each other,and the molecule also possesses a plane of symmetry.Since both isomers possess a plane of symmetry,they are achiral and therefore optically inactive.Thus,both statements are true and $STATEMENT-2$ is the correct explanation for $STATEMENT-1$.

$STATEMENT-1$: The geometrical isomers of the complex $[M(NH_3)_4Cl_2]$ are optically inactive.
$STATEMENT-2$: Both geometrical isomers of the complex $[M(NH_3)_4Cl_2]$ possess a plane of symmetry.

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$STATEMENT-1$: The geometrical isomers of the complex $[M(NH_3)_4Cl_2]$ are optically inactive.$STATEMENT-2$: Both geometrical isomers of the complex $[M(NH_3)_4Cl_2]$ possess a plane of symmetry.