KI in acetone undergoes S_N2 reaction with ea | vedclass

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(B) The rate of $S_N2$ reaction depends on steric hindrance and the presence of electron-withdrawing groups at the $\alpha$-carbon.$1$. $S$ $(C_6H_5-C

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$S > R > P > Q$

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(B) The rate of $S_N2$ reaction depends on steric hindrance and the presence of electron-withdrawing groups at the $\alpha$-carbon.$1$. $S$ $(C_6H_5-CO-CH_2-Cl)$: The carbonyl group $(C=O)$ is strongly electron-withdrawing due to the $-I$ and $-M$ effects,which stabilizes the transition state,making it highly reactive.$2$. $R$ $(CH_2=CH-CH_2-Cl)$: This is an allylic halide. The transition state is stabilized by conjugation with the double bond,making it more reactive than primary alkyl halides.$3$. $P$ $(CH_3-Cl)$: This is a primary alkyl halide with minimal steric hindrance.$4$. $Q$ $((CH_3)_2CH-Cl)$: This is a secondary alkyl halide,which is the least reactive due to higher steric hindrance compared to the others.Therefore,the order of reactivity is $S > R > P > Q$.

$KI$ in acetone undergoes $S_N2$ reaction with each $P, Q, R$ and $S$. The rates of the reaction vary as:
$P: CH_3-Cl$
$Q: (CH_3)_2CH-Cl$
$R: CH_2=CH-CH_2-Cl$
$S: C_6H_5-CO-CH_2-Cl$

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$KI$ in acetone undergoes $S_N2$ reaction with each $P, Q, R$ and $S$. The rates of the reaction vary as:$P: CH_3-Cl$$Q: (CH_3)_2CH-Cl$$R: CH_2=CH-CH_2-Cl$$S: C_6H_5-CO-CH_2-Cl$