$A$ series $LCR$ circuit is connected to an alternating source of emf $E$. The current amplitude at resonant frequency is $I_0$. If the value of resistance $R$ becomes twice of its initial value,then the amplitude of current at resonance will be

  • A
    $I_0$
  • B
    $\frac{I_0}{2}$
  • C
    $\frac{I_0}{\sqrt{2}}$
  • D
    $2 I_0$

Explore More

Similar Questions

Assertion: In a series $LCR$ circuit,resonance can take place.
Reason: Resonance takes place if inductive and capacitive reactances are equal and opposite.

In an $LCR$ oscillatory circuit,find the energy stored in the inductor at resonance. If the voltage of the source is $10 \, V$,the resistance is $10 \, \Omega$,and the inductance is $1 \, H$. (in $J$)

For an $RLC$ circuit driven with voltage of amplitude $v_m$ and frequency $\omega_0 = \frac{1}{\sqrt{LC}}$,the current exhibits resonance. The quality factor,$Q$,is given by:

$A$ series $LCR$ circuit is connected to an ac source of $220\,V, 50\,Hz$. The circuit contains a resistance $R=100\,\Omega$ and an inductor of inductive reactance $X_L=79.6\,\Omega$. The capacitance of the capacitor needed to maximize the average rate at which energy is supplied will be $..........\mu F$.

In an $LCR$ series circuit, at resonance,

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo