$A$ particle is executing simple harmonic motion with time period $2 \ s$ and amplitude $1 \ cm$. If $D$ and $d$ are the total distance and displacement covered by the particle in $12.5 \ s$,then $\frac{D}{d}$ is:

  • A
    $\frac{15}{4}$
  • B
    $25$
  • C
    $10$
  • D
    $\frac{16}{5}$

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