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(B) For a gas in a container of fixed volume,the volume $V$ is constant. According to Gay-Lussac's Law,for a fixed amount of gas at constant volume,th

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$327$

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(B) For a gas in a container of fixed volume,the volume $V$ is constant. According to Gay-Lussac's Law,for a fixed amount of gas at constant volume,the pressure $P$ is directly proportional to the absolute temperature $T$ ($P \propto T$ or $\frac{P_1}{T_1} = \frac{P_2}{T_2}$).Given initial temperature $T_1 = 27^{\circ} C = 27 + 273 = 300 \ K$.Let the initial pressure be $P_1 = P$.We want the final pressure to be $P_2 = 2P$.Using the relation $\frac{P_1}{T_1} = \frac{P_2}{T_2}$:$\frac{P}{300} = \frac{2P}{T_2}$$T_2 = 2 	imes 300 = 600 \ K$.To convert the temperature back to Celsius: $T_2(^{\circ} C) = 600 - 273 = 327^{\circ} C$.

$A$ container of fixed volume contains a gas at $27^{\circ} C$. To double the pressure of the gas,the temperature of the gas should be raised to . . . . . . ${ }^{\circ} {C}$.

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