A slanted object AB is placed on one side of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For point $A$,the object distance is $u = -30 \ cm$ and the focal length is $f = +20 \ cm$. Using the lens formula $\frac{1}{v} - \frac{1}{u} = \f

Vedclass · Accepted Answer

$-45^{\circ}$

Vedclass · Answer

(B) For point $A$,the object distance is $u = -30 \ cm$ and the focal length is $f = +20 \ cm$. Using the lens formula $\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$:$\frac{1}{v} - \frac{1}{-30} = \frac{1}{20} \Rightarrow \frac{1}{v} = \frac{1}{20} - \frac{1}{30} = \frac{3-2}{60} = \frac{1}{60}$.Thus,$v = 60 \ cm$. The magnification is $m = \frac{v}{u} = \frac{60}{-30} = -2$.For a small object,the longitudinal magnification is $m_L = \frac{dv}{du} = m^2 = (-2)^2 = 4$. The change in image position is $dv = m^2 du = 4 	imes 1 \ cm = 4 \ cm$.The transverse magnification is $m = \frac{h_i}{h_o} = -2$,so the height of the image is $h_i = m 	imes h_o = -2 	imes 2 \ cm = -4 \ cm$.The image is inverted and real. The angle $	heta$ made by the image with the principal axis is given by $	an 	heta = \frac{|h_i|}{|dv|} = \frac{4}{4} = 1$. Since the image is inverted,the angle is $-45^{\circ}$.

$A$ slanted object $AB$ is placed on one side of a convex lens as shown in the diagram. The image is formed on the opposite side. The angle made by the image with the principal axis is

Similar Questions

$A$ double convex lens of glass of $\mu = 1.5$ has a radius of curvature of each of its surfaces equal to $0.2 \ m$. The power of the lens is:

$A$ photograph of a landscape is captured by a drone camera at a height of $18 \ \text{km}$. The size of the camera film is $2 \ \text{cm} \times 2 \ \text{cm}$ and the area of the landscape photographed is $400 \ \text{km}^2$. The focal length of the lens in the drone camera is: (in $\text{cm}$)

$A$ convex lens of focal length $f$ produces a real image whose size is $n$ times the size of an object. The distance of the object from the lens is

The following graph depicts the inverse of magnification $(1/m)$ versus the distance between the object and the lens $(u)$ for a setup. The focal length of the lens used in the setup is .................... $m$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module