A person measures the mass of 3 different par | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The given masses are $m_1 = 435.42 \ g$,$m_2 = 226.3 \ g$,and $m_3 = 0.125 \ g$.To find the sum,we add them: $435.42 + 226.3 + 0.125 = 661.845 \ g

Vedclass · Accepted Answer

$661.8$

Vedclass · Answer

(C) The given masses are $m_1 = 435.42 \ g$,$m_2 = 226.3 \ g$,and $m_3 = 0.125 \ g$.To find the sum,we add them: $435.42 + 226.3 + 0.125 = 661.845 \ g$.According to the rules for addition with significant figures,the final result should be reported to the same number of decimal places as the measurement with the fewest decimal places.The measurements have $2$,$1$,and $3$ decimal places respectively. The least number of decimal places is $1$.Therefore,rounding $661.845 \ g$ to one decimal place gives $661.8 \ g$.

$A$ person measures the mass of $3$ different particles as $435.42 \ g$,$226.3 \ g$,and $0.125 \ g$. According to the rules for arithmetic operations with significant figures,the sum of the masses of the $3$ particles will be: (in $g$)

Similar Questions

The length of the side of a cube is $1.2 \times 10^{-2} \ m$. Its volume up to correct significant figures is

The number of significant figures in all the given numbers $25.12, 2009, 4.156$ and $1.217 \times 10^{-4}$ is

The volume of a sphere is $1.76 \ cm^3$. The volume of $25$ such spheres,taking into account significant figures,is:

$A$ body of mass $m = 3.513 \; kg$ is moving along the $x$-axis with a speed of $5.00 \; ms^{-1}$. The magnitude of its momentum is recorded as (Consider significant figures):

Round off the value $2.845$ to three significant figures.

Vedclass Test Series

Exam Paper Generator

Online Exam Module