A dipole with two electric charges of 2 mu C | vedclass

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Question

(A) The electric field $E$ between the plates of the capacitor is given by $E = \frac{V}{d}$,where $V = 5 \ V$ and $d = 0.5 \ mm = 5 	imes 10^{-4} \

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$5 	imes 10^{-9} \ Nm$

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(A) The electric field $E$ between the plates of the capacitor is given by $E = \frac{V}{d}$,where $V = 5 \ V$ and $d = 0.5 \ mm = 5 	imes 10^{-4} \ m$.$E = \frac{5}{5 	imes 10^{-4}} = 10^4 \ V/m$.The dipole moment $p$ is given by $p = q 	imes a$,where $q = 2 \ \mu C = 2 	imes 10^{-6} \ C$ and $a = 0.5 \ \mu m = 5 	imes 10^{-7} \ m$.$p = 2 	imes 10^{-6} 	imes 5 	imes 10^{-7} = 1 	imes 10^{-12} \ C \cdot m$.The torque $	au$ acting on the dipole is given by $	au = pE \sin 	heta$,where $	heta = 30^{\circ}$.$	au = (1 	imes 10^{-12} \ C \cdot m) 	imes (10^4 \ V/m) 	imes \sin(30^{\circ})$.$	au = 10^{-8} 	imes 0.5 = 5 	imes 10^{-9} \ N \cdot m$.

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