A photoelectric cell is connected to a source | vedclass

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(C) $1$. The saturation photoelectric current is directly proportional to the intensity of the incident radiation. Since the intensity is reduced,the

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$C$

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(C) $1$. The saturation photoelectric current is directly proportional to the intensity of the incident radiation. Since the intensity is reduced,the saturation current for the new situation must be lower than the original (broken line) graph.$2$. The stopping potential is directly proportional to the frequency of the incident radiation. Since the frequency is increased,the magnitude of the stopping potential must increase (i.e.,it becomes more negative).$3$. Comparing the given options,graph $C$ shows a lower saturation current and a higher magnitude of stopping potential compared to the broken line graph. Therefore,graph $C$ represents the new situation.

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