A sulphur-containing species that can not act | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) To act as a reducing agent,a species must be able to increase its oxidation state (i.e.,undergo oxidation).In $SO_2$,the oxidation state of $S$ is

Vedclass · Accepted Answer

$H_2SO_4$

Vedclass · Answer

(C) To act as a reducing agent,a species must be able to increase its oxidation state (i.e.,undergo oxidation).In $SO_2$,the oxidation state of $S$ is $+4$ (can increase to $+6$).In $SO_3^{2-}$,the oxidation state of $S$ is $+4$ (can increase to $+6$).In $S^{2-}$,the oxidation state of $S$ is $-2$ (can increase to $0$ or higher).In $H_2SO_4$,the oxidation state of $S$ is $+6$,which is the maximum possible oxidation state for sulphur.Therefore,$H_2SO_4$ cannot be further oxidized and cannot act as a reducing agent.

$A$ sulphur-containing species that can not act as a reducing agent is

Similar Questions

Consider the following reaction:
$BrCH_2CH_2F + SbF_5 \xrightarrow{SO_2, -60^{\circ}C} CH_2-CH_2-Br^+ + SbF_6^-$
In this reaction,$SbF_5$ acts as:

Which acts as an oxidising agent in the following reaction?
$2H_2O_{(l)} + 2Na_{(s)} \to 2NaOH_{(aq)} + H_{2_{(g)}}$

$Br^{-}$ is converted into $Br_2$ by using:

Which of the following species acts as the weakest reducing agent?

Which is a mild oxidising agent?

Vedclass Test Series

Exam Paper Generator

Online Exam Module