A normal-visioned man whose father was colour | vedclass

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(B) Colour blindness is an $X$-linked recessive trait.$1$. The man is normal-visioned,so his genotype is $X^CY$ (where $X^C$ is the normal allele and

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(B) Colour blindness is an $X$-linked recessive trait.$1$. The man is normal-visioned,so his genotype is $X^CY$ (where $X^C$ is the normal allele and $X^c$ is the colourblind allele). Since his father was colourblind,he inherited his $Y$ chromosome from his father and his $X^C$ chromosome from his mother.$2$. The woman is normal-visioned but her father was colourblind. This means she must be a carrier,with the genotype $X^CX^c$.$3$. The cross is $X^CY 	imes X^CX^c$.$4$. The possible genotypes of the offspring are: $X^CX^C$ (normal daughter),$X^CX^c$ (carrier daughter),$X^CY$ (normal son),and $X^cY$ (colourblind son).$5$. Among the sons,the genotypes are $X^CY$ and $X^cY$. Thus,the probability of the son being colourblind is $1/2$ or $50 \%$.

$A$ normal-visioned man whose father was colourblind marries a normal woman whose father was also colourblind. They have one son. What is the probability of the son being colourblind (in $\%$)?

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