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(D) The balanced chemical equation is $A + 2B \rightarrow 3C$.According to the stoichiometry,$1$ mole of $A$ reacts with $2$ moles of $B$ to produce $

Vedclass · Accepted Answer

$21$

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(D) The balanced chemical equation is $A + 2B ightarrow 3C$.According to the stoichiometry,$1$ mole of $A$ reacts with $2$ moles of $B$ to produce $3$ moles of $C$.Given moles of $A = 20$ and moles of $B = 14$.To find the limiting reagent,calculate the ratio of moles to stoichiometric coefficient:For $A$: $20 / 1 = 20$.For $B$: $14 / 2 = 7$.Since the ratio for $B$ is smaller,$B$ is the limiting reagent.The amount of $C$ produced depends on the limiting reagent $B$.From the equation,$2$ moles of $B$ produce $3$ moles of $C$.Therefore,$14$ moles of $B$ will produce $(3 / 2) 	imes 14 = 21$ moles of $C$.

$20$ moles of $A$ and $14$ moles of $B$ are mixed and allowed to react according to the equation $A + 2B \rightarrow 3C$. What is the maximum number of moles of $C$ which could be prepared?

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