$Ph-CH=CH-CH_3$ $\xrightarrow[H_2O_2/OH^-]{B_2H_6/THF}$ Products. Reaction $(A)$
$CH_3-CH=CH-Ph$ $\xrightarrow[NaBH_4]{Hg(OAc)_2/H_2O}$ Products. Reaction $(B)$
Which statement is correct?

• A
  In reaction $(A)$,the product is formed according to the Markownikoff rule.
• B
  In reaction $(B)$,the product is formed according to the Antimarkownikoff rule.
• C
  In reaction $(A)$,the product is a meso compound.
• D
  In reaction $(B)$,the product is a racemic mixture.