$A$ liquid of specific heat $0.8 \ cal / g^{\circ} C$ at temperature $60^{\circ} C$ is mixed with another liquid of the same mass having temperature $45^{\circ} C$. If the temperature of the mixture is $53^{\circ} C$,then the specific heat (in $cal / g^{\circ} C$) of the second liquid is:

An electric kettle (rated at $2.5\, kW$) is used to heat $3\, kg$ of water from $15\, ^oC$ to its boiling point. It takes $9.5$ minutes. The amount of heat lost is:

Two liquids $A$ and $B$ are at $32^{\circ}C$ and $24^{\circ}C$. When mixed in equal masses,the temperature of the mixture is found to be $28^{\circ}C$. Their specific heats are in the ratio of:

Time taken by a $836\; W$ heater to heat $1\; litre$ of water from $10^{\circ} C$ to $40^{\circ} C$ is (in $; s$)

$A$ $50 \,g$ ice cube at $-10^{\circ} C$ is added to $200 \,g$ of water at $30^{\circ} C$. The final temperature of the mixture is (specific heat of water $= 1 \,cal \,g^{-1} {}^{\circ} C^{-1}$,latent heat of fusion of ice $= 80 \,cal \,g^{-1}$,specific heat of ice $= 0.5 \,cal \,g^{-1} {}^{\circ} C^{-1}$). (in $^{\circ} C$)

$50\, g$ of ice at $0^{\circ}C$ is mixed with $50\, g$ of water at $80^{\circ}C$. The final temperature of the mixture will be........ $^{\circ}C$.