A reaction of phenol with chloroform in the p | vedclass

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(A) When phenol is treated with chloroform $(CHCl_3)$ in the presence of aqueous sodium hydroxide $(NaOH)$,a formyl group $(-CHO)$ is introduced at th

Vedclass · Accepted Answer

Reimer-Tiemann reaction

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(A) When phenol is treated with chloroform $(CHCl_3)$ in the presence of aqueous sodium hydroxide $(NaOH)$,a formyl group $(-CHO)$ is introduced at the ortho position of the benzene ring.This reaction is known as the Reimer-Tiemann reaction.The reaction proceeds through the formation of a dichlorocarbene intermediate $(:CCl_2)$,which acts as an electrophile.The final product obtained after acidification is salicylaldehyde (o-hydroxybenzaldehyde).

$A$ reaction of phenol with chloroform in the presence of sodium hydroxide to form salicylaldehyde is known as

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