$Methyl$ propanoate on hydrolysis with dil. $NaOH$ forms a salt which on further acidification with conc. $HCl$ forms . . . . . . .

  • A
    $CH_3-CH_2-COOH$
  • B
    $CH_3-COOH$
  • C
    $CH_3-CH_2-OH$
  • D
    $HCOOH$

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