1-chlorobutane on reaction with alcoholic pot | vedclass

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Question

(A) The reaction of $1$-chlorobutane $(CH_3-CH_2-CH_2-CH_2-Cl)$ with alcoholic $KOH$ is a dehydrohalogenation reaction.In this reaction,an $H$ atom is

Vedclass · Accepted Answer

but-$1$-ene

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(A) The reaction of $1$-chlorobutane $(CH_3-CH_2-CH_2-CH_2-Cl)$ with alcoholic $KOH$ is a dehydrohalogenation reaction.In this reaction,an $H$ atom is removed from the $\beta$-carbon and the $Cl$ atom is removed from the $\alpha$-carbon,resulting in the formation of an alkene.The reaction proceeds as follows:$CH_3-CH_2-CH_2-CH_2-Cl + 	ext{alc. } KOH \xrightarrow{\Delta} CH_3-CH_2-CH=CH_2 + KCl + H_2O$The product formed is but-$1$-ene.

$1$-chlorobutane on reaction with alcoholic potash gives

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