$n$ gentlemen can be made to sit on a round table in how many ways?
- A$\frac{1}{2}(n + 1)!$ ways
- B$(n - 1)!$ ways
- C$\frac{1}{2}(n - 1)!$ ways
- D$(n + 1)!$ ways
Explore More
Similar Questions
The number of ways in which $6$ men and $5$ women can sit at a round table,if no two women sit together,is:
The number of ways in which $5$ boys and $4$ girls can sit around a circular table such that no two girls sit together is:
$8$ teachers and $4$ students are sitting around a circular table at random. Then,the probability that no two students sit together is:
The number of ways in which $5$ beads of different colours form a necklace is
Easy
View SolutionThe number of ways in which $6$ men and $5$ women can dine at a round table if no two women are to sit together is given by
MediumAIEEE 2003
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo