A metal has BCC structure with edge length of | vedclass

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(D) The formula for density is $d = \frac{Z \cdot M}{N_A \cdot a^3}$.Given:$Z = 2$ (for $BCC$ structure)$a = 400 \ pm = 400 	imes 10^{-10} \ cm = 4 \

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$77 \ g \ mol^{-1}$

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(D) The formula for density is $d = \frac{Z \cdot M}{N_A \cdot a^3}$.Given:$Z = 2$ (for $BCC$ structure)$a = 400 \ pm = 400 	imes 10^{-10} \ cm = 4 	imes 10^{-8} \ cm$$d = 4 \ g \ cm^{-3}$$N_A = 6.022 	imes 10^{23} \ mol^{-1}$Rearranging for molar mass $M$:$M = \frac{d \cdot N_A \cdot a^3}{Z}$Substituting the values:$M = \frac{4 \cdot 6.022 	imes 10^{23} \cdot (4 	imes 10^{-8})^3}{2}$$M = \frac{4 \cdot 6.022 	imes 10^{23} \cdot 64 	imes 10^{-24}}{2}$$M = 2 \cdot 6.022 \cdot 64 \cdot 10^{-1}$$M = 77.08 \ g \ mol^{-1} \approx 77 \ g \ mol^{-1}$.

$A$ metal has $BCC$ structure with edge length of unit cell $400 \ pm$. The density of the metal is $4 \ g \ cm^{-3}$. What is the molar mass of the metal?

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