$9 \ g$ anhydrous oxalic acid (mol. $Wt. = 90$) was dissolved in $9.9 \ moles$ of water. If vapour pressure of pure water is $P_1^o$,the vapour pressure of solution is (in $P_1^o$)

  • A
    $0.99$
  • B
    $0.1$
  • C
    $0.91$
  • D
    $1.1$

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