0.2 M aqueous solution of glucose has osmoti | vedclass

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(D) The osmotic pressure $\pi$ is given by the formula $\pi = M 	imes R 	imes T$,where $M$ is the molar concentration,$R$ is the gas constant,and $T

Vedclass · Accepted Answer

$0.06$

Vedclass · Answer

(D) The osmotic pressure $\pi$ is given by the formula $\pi = M 	imes R 	imes T$,where $M$ is the molar concentration,$R$ is the gas constant,and $T$ is the temperature in Kelvin.Since $R$ and $T$ are constant for both cases,we have the relationship $\frac{\pi_1}{M_1} = \frac{\pi_2}{M_2}$.Given $\pi_1 = 4.9 \ atm$,$M_1 = 0.2 \ M$,and $\pi_2 = 1.5 \ atm$.Substituting the values: $\frac{4.9}{0.2} = \frac{1.5}{M_2}$.$M_2 = \frac{1.5 	imes 0.2}{4.9} = \frac{0.3}{4.9} \approx 0.0612 \ M$.Rounding to the nearest option,the concentration is $0.06 \ M$.

$0.2 \ M$ aqueous solution of glucose has osmotic pressure $4.9 \ atm$ at $300 \ K$. What is the concentration of glucose if it has osmotic pressure $1.5 \ atm$ at same temperature (in $M$)?

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