(B) According to the law of definite proportion,the percentage composition of a compound remains constant regardless of its source.Given that $Ca$ con

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(B) According to the law of definite proportion,the percentage composition of a compound remains constant regardless of its source.Given that $Ca$ constitutes $40 \%$ of the sample by mass.Therefore,in a $4 \ g$ sample of calcium carbonate,the mass of calcium is calculated as:$\text{Mass of } Ca = \frac{40}{100} \times 4 \ g = 1.6 \ g$.

Class 11 Chemistry Some Basic Concepts of Chemistry Laws of chemical combination

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$A$ sample of calcium carbonate has the following percentage composition: $Ca = 40 \%$,$C = 12 \%$,and $O = 48 \%$. According to the law of definite proportion,the weight of calcium in $4 \ g$ of a sample of calcium carbonate from another source will be (atomic weights: $Ca = 40, C = 12, O = 16$).

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A
$1.6 \times 10^{-2} \ g$
B
$1.6 \ g$
C
$0.1 \ g$
D
$0.2 \ g$

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Class 11

Chemistry Questions

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Some Basic Concepts of Chemistry

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Laws of chemical combination

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$A$ box contains some identical red-coloured balls,labelled as $A$,each weighing $2 \ g$. Another box contains identical blue-coloured balls,labelled as $B$,each weighing $5 \ g$. Consider the combinations $AB, AB_2, A_2B$ and $A_2B_3$ and show that the law of multiple proportions is applicable.

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When two elements combine to form more than one compound,the masses of one element that combine with a fixed mass of the other element are in a simple whole number ratio.
$(a)$ Is the statement given above correct?
$(b)$ If 'yes',which law does it follow?
$(c)$ Give an example corresponding to this law.

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$A$ pure sample of water contains $88.89\%$ of oxygen by mass and $11.11\%$ of hydrogen by mass. This is an example of which law?

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The law of multiple proportions is illustrated by the two compounds:

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In compound $A$,$1.00 \, g$ nitrogen unites with $0.57 \, g$ oxygen. In compound $B$,$2.00 \, g$ nitrogen combines with $2.24 \, g$ oxygen. In compound $C$,$3.00 \, g$ nitrogen combines with $5.11 \, g$ oxygen. These results obey the following law:

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$A$ sample of calcium carbonate has the following percentage composition: $Ca = 40 \%$,$C = 12 \%$,and $O = 48 \%$. According to the law of definite proportion,the weight of calcium in $4 \ g$ of a sample of calcium carbonate from another source will be (atomic weights: $Ca = 40, C = 12, O = 16$).

Similar Questions

$A$ box contains some identical red-coloured balls,labelled as $A$,each weighing $2 \ g$. Another box contains identical blue-coloured balls,labelled as $B$,each weighing $5 \ g$. Consider the combinations $AB, AB_2, A_2B$ and $A_2B_3$ and show that the law of multiple proportions is applicable.

$A$ pure sample of water contains $88.89\%$ of oxygen by mass and $11.11\%$ of hydrogen by mass. This is an example of which law?

The law of multiple proportions is illustrated by the two compounds:

In compound $A$,$1.00 \, g$ nitrogen unites with $0.57 \, g$ oxygen. In compound $B$,$2.00 \, g$ nitrogen combines with $2.24 \, g$ oxygen. In compound $C$,$3.00 \, g$ nitrogen combines with $5.11 \, g$ oxygen. These results obey the following law:

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