$A$ man is known to speak the truth $3$ out of $4$ times. He throws a die and reports that it is $6$. Then the probability that it is actually $6$ is:

  • A
    $\frac{3}{4}$
  • B
    $\frac{1}{4}$
  • C
    $\frac{3}{8}$
  • D
    $\frac{5}{6}$

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