operatorname{cosec} 2 theta - cot 2 theta = ? | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) We know that $\operatorname{cosec} 2 	heta = \frac{1}{\sin 2 	heta}$ and $\cot 2 	heta = \frac{\cos 2 	heta}{\sin 2 	heta}$.Substituting thes

Vedclass · Accepted Answer

$	an 	heta$

Vedclass · Answer

(A) We know that $\operatorname{cosec} 2 	heta = \frac{1}{\sin 2 	heta}$ and $\cot 2 	heta = \frac{\cos 2 	heta}{\sin 2 	heta}$.Substituting these in the expression:$\operatorname{cosec} 2 	heta - \cot 2 	heta = \frac{1}{\sin 2 	heta} - \frac{\cos 2 	heta}{\sin 2 	heta} = \frac{1 - \cos 2 	heta}{\sin 2 	heta}$.Using the trigonometric identities $1 - \cos 2 	heta = 2 \sin^2 	heta$ and $\sin 2 	heta = 2 \sin 	heta \cos 	heta$:$= \frac{2 \sin^2 	heta}{2 \sin 	heta \cos 	heta} = \frac{\sin 	heta}{\cos 	heta} = 	an 	heta$.Thus,the correct option is $A$.

$\operatorname{cosec} 2 \theta - \cot 2 \theta = ?$

Similar Questions

$\sqrt{2 + \sqrt{2 + 2\cos 4\theta}} = $

Evaluate: $\cos \frac{\pi}{5} \cos \frac{2\pi}{5} \cos \frac{4\pi}{5} \cos \frac{8\pi}{5}$

If $\cos A = \frac{3}{4}$,then $32 \sin \left(\frac{A}{2}\right) \sin \left(\frac{5A}{2}\right) = $

$(4 \cos^2 9^{\circ} - 3)(4 \cos^2 27^{\circ} - 3) = $

If $\sin x + \cos x = \frac{1}{5},$ then $\tan 2x$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module