(D) This is a case of a perfectly inelastic collision.In any collision where external forces are absent,the total linear momentum of the system is con

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(D) This is a case of a perfectly inelastic collision.In any collision where external forces are absent,the total linear momentum of the system is conserved.However,in an inelastic collision,some kinetic energy is converted into other forms of energy (such as heat or deformation energy) due to the internal forces acting during the impact.Therefore,only the linear momentum is conserved,while the kinetic energy is not.

Class 11 Physics Work, Energy, Power and Collision Perfectly Inelastic Collision

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$A$ bullet is fired from a gun. It hits a solid block resting on a frictionless surface,gets embedded into it,and both move jointly. In this process,

MHT CET 2022 All MHT CET

A
Both momentum and kinetic energy are not conserved.
B
Only kinetic energy is conserved.
C
Both momentum and kinetic energy are conserved.
D
Only momentum is conserved.

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Class 11

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Work, Energy, Power and Collision

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Perfectly Inelastic Collision

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$A$ body of mass $2 \, kg$ moving with a velocity $(\hat{i} + \hat{j} + \hat{k}) \, m/s$ collides with another body of mass $5 \, kg$ moving with velocity $(\hat{i} - 2\hat{j} + 3\hat{k}) \, m/s$. If they stick together,the velocity (in $m/s$) of the composite body is:

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$A$ block of mass $10 \text{ g}$ is suspended from the ceiling by a string. $A$ bullet of mass $10 \text{ g}$ moving with a velocity of $1 \text{ m/s}$ strikes the block and gets embedded in it. To what height will the block rise (in $\text{ cm}$)? (Take $g = 10 \text{ m/s}^2$)

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In a one-dimensional collision, a particle of mass $2m$ collides with a particle of mass $m$ at rest. If the particles stick together after the collision, what fraction of the initial kinetic energy is lost in the collision?

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$A$ mass $M$ moving with velocity $V$ along the $x$-axis collides and sticks to another mass $2M$ which is moving along the $y$-axis with velocity $3V$. The velocity of the combination after the collision is:

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Two particles $A$ and $B$ of equal mass $M$ are moving with the same speed $v$ as shown in the figure. They collide completely inelastically and move as a single particle $C$. The angle $\theta$ that the path of $C$ makes with the $X$-axis is given by

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$A$ bullet is fired from a gun. It hits a solid block resting on a frictionless surface,gets embedded into it,and both move jointly. In this process,

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$A$ body of mass $2 \, kg$ moving with a velocity $(\hat{i} + \hat{j} + \hat{k}) \, m/s$ collides with another body of mass $5 \, kg$ moving with velocity $(\hat{i} - 2\hat{j} + 3\hat{k}) \, m/s$. If they stick together,the velocity (in $m/s$) of the composite body is:

$A$ block of mass $10 \text{ g}$ is suspended from the ceiling by a string. $A$ bullet of mass $10 \text{ g}$ moving with a velocity of $1 \text{ m/s}$ strikes the block and gets embedded in it. To what height will the block rise (in $\text{ cm}$)? (Take $g = 10 \text{ m/s}^2$)

In a one-dimensional collision, a particle of mass $2m$ collides with a particle of mass $m$ at rest. If the particles stick together after the collision, what fraction of the initial kinetic energy is lost in the collision?

$A$ mass $M$ moving with velocity $V$ along the $x$-axis collides and sticks to another mass $2M$ which is moving along the $y$-axis with velocity $3V$. The velocity of the combination after the collision is:

Two particles $A$ and $B$ of equal mass $M$ are moving with the same speed $v$ as shown in the figure. They collide completely inelastically and move as a single particle $C$. The angle $\theta$ that the path of $C$ makes with the $X$-axis is given by

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