A magnetic field of 2 times 10^{-2} ,T acts a | vedclass

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(C) The magnetic flux linked with the coil is given by $\phi = NBA \cos 	heta$. Since the field is at right angles to the coil, $	heta = 0^\circ$ an

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$0.1 \,s$

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(C) The magnetic flux linked with the coil is given by $\phi = NBA \cos 	heta$. Since the field is at right angles to the coil, $	heta = 0^\circ$ and $\cos 0^\circ = 1$.Initial flux $\phi_1 = NBA = 50 	imes (2 	imes 10^{-2} \,T) 	imes (100 	imes 10^{-4} \,m^2) = 50 	imes 2 	imes 10^{-2} 	imes 10^{-2} = 10^{-2} \,Wb$.Final flux $\phi_2 = 0$ (as it is removed from the field).The magnitude of induced e.m.f. is given by $|e| = \frac{|\Delta \phi|}{t} = \frac{|\phi_2 - \phi_1|}{t}$.Substituting the values: $0.1 = \frac{|0 - 10^{-2}|}{t}$.Therefore, $t = \frac{10^{-2}}{0.1} = 0.1 \,s$.

$A$ magnetic field of $2 \times 10^{-2} \,T$ acts at right angles to a coil of area $100 \,cm^2$ with $50$ turns. The average e.m.f. induced in the coil is $0.1 \,V$, when it is removed from the field in time '$t$'. The value of '$t$' is

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