$A$ coil has an area $0.06 \ m^2$ and it has $600$ turns. After placing the coil in a magnetic field of strength $5 \times 10^{-5} \ Wb/m^2$,it is rotated through $90^{\circ}$ in $0.2 \ s$. The magnitude of average e.m.f induced in the coil is

$A$ circular coil has $100$ turns,radius $3 \ cm$ and resistance $4 \Omega$. This coil is co-axial with a solenoid of $200$ turns/cm and diameter $4 \ cm$. If the solenoid current is decreased from $2 \ A$ to zero in $0.04 \ s$,then the current induced in the coil is

The direction of induced e.m.f. during electromagnetic induction is given by

Suppose a long solenoid of $100 \ cm$ length, radius $2 \ cm$ having $500 \ turns/cm$ carries a current $I = 10 \sin(\omega t) \ A$, where $\omega = 1000 \ rad/s$. $A$ circular conducting loop $(B)$ of radius $1 \ cm$ is coaxially placed inside the solenoid. The r.m.s. current through the loop when the coil $B$ is inside the solenoid is $\alpha / \sqrt{2} \ \mu A$. The value of $\alpha$ is . . . . . . . [Resistance of the loop $= 10 \ \Omega$]

Consider the experiment shown in the figure.
$(a)$ What would you do to obtain a large deflection of the galvanometer?
$(b)$ How would you demonstrate the presence of an induced current in the absence of a galvanometer?

$A$ coil having $100$ turns and an area of $1 \times 10^{-3} \ m^2$ is placed in a magnetic field of $1 \ Wb/m^2$. If the magnetic field is reversed,what is the total charge that flows through the circuit,given that the resistance of the circuit is $10 \ \Omega$?