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(D) According to Gauss's Law,the total electric flux $\Phi$ through a closed surface is given by $\Phi = \frac{q_{enclosed}}{\varepsilon_0}$.Here,$q_{

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Remains unchanged

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(D) According to Gauss's Law,the total electric flux $\Phi$ through a closed surface is given by $\Phi = \frac{q_{enclosed}}{\varepsilon_0}$.Here,$q_{enclosed}$ is the total charge enclosed by the surface and $\varepsilon_0$ is the permittivity of free space.When the balloon is blown up,its size increases,but the total charge $q$ on the surface of the balloon remains constant.Since the charge enclosed by the surface does not change,the total electric flux $\Phi = \frac{q}{\varepsilon_0}$ also remains unchanged.

$A$ spherical rubber balloon carries a charge,uniformly distributed over the surface. As the balloon is blown up and increases in size,the total electric flux coming out of the surface

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