A body weighs 500 ,N on the surface of the ea | vedclass

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(B) The value of acceleration due to gravity decreases as we go below the surface of the earth. The weight $(W)$ of a body is defined as the product o

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$3200$

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(B) The value of acceleration due to gravity decreases as we go below the surface of the earth. The weight $(W)$ of a body is defined as the product of its mass $(m)$ and the acceleration due to gravity $(g)$, i.e., $W = mg$.At a depth $h$ below the surface of the earth, the acceleration due to gravity $g'$ is given by the formula:$g' = g \left(1 - \frac{h}{R}ight)$Multiplying both sides by mass $m$, we get the weight at depth $h$:$W' = W \left(1 - \frac{h}{R}ight)$Given that $W' = 250 \,N$, $W = 500 \,N$, and $R = 6400 \,km$:$250 = 500 \left(1 - \frac{h}{6400}ight)$$0.5 = 1 - \frac{h}{6400}$$\frac{h}{6400} = 0.5$$h = 0.5 	imes 6400 = 3200 \,km$.

$A$ body weighs $500 \,N$ on the surface of the earth. At what distance below the surface of the earth will it weigh $250 \,N$ (in $\,km$)? (Radius of earth, $R = 6400 \,km$)

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