A machine gun fires a bullet of mass 35 g wi | vedclass

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(C) The force exerted by the machine gun is equal to the rate of change of momentum of the bullets.Let $n$ be the number of bullets fired per second.T

Vedclass · Accepted Answer

$7$

Vedclass · Answer

(C) The force exerted by the machine gun is equal to the rate of change of momentum of the bullets.Let $n$ be the number of bullets fired per second.The mass of each bullet is $m = 35 \ g = 0.035 \ kg$.The velocity of each bullet is $v = 600 \ m/s$.The force $F$ exerted by the gun is given by the formula $F = n 	imes (m 	imes v)$.Given $F = 147 \ N$,$m = 0.035 \ kg$,and $v = 600 \ m/s$.Substituting the values: $147 = n 	imes (0.035 	imes 600)$.$147 = n 	imes 21$.$n = 147 / 21 = 7$.Therefore,the number of bullets that can be fired per second is $7$.

$A$ machine gun fires a bullet of mass $35 \ g$ with a speed of $600 \ m/s$. The person holding the gun can exert a maximum force of $147 \ N$ on it. The number of bullets that can be fired from the gun per second is

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