$A$ force is applied to a body of mass $2 \,kg$ at rest on a frictionless horizontal surface, as shown in the force-time $(F-t)$ graph. The speed of the body after $1 \,s$ is: (in $\,m/s$)

$A$ particle moves in the $x-y$ plane under the influence of a force $\vec{F}$ such that its linear momentum is $\vec{P}(t) = \hat{i} \cos(kt) - \hat{j} \sin(kt)$. If $k$ is a constant,the angle between $\vec{F}$ and $\vec{P}$ will be:

Why does a cricket player move their hands backward while catching a fast-moving ball?

$A$ rigid ball of mass $m$ strikes a rigid wall at $60^\circ$ and gets reflected without loss of speed as shown in the figure. The value of impulse imparted by the wall on the ball will be

The force $F$ acting on a particle of mass $m$ is indicated by the force-time graph shown below. The change in momentum of the particle over the time interval from $0 \, s$ to $8 \, s$ is .......... $N-s$.

$A$ ball of mass $0.2 \ kg$ moving with a speed of $20 \ m s^{-1}$ is brought to rest in $0.1 \ s$. The average force applied to the ball is (in $N$)