$A$ coil having $9$ turns carrying current $I$ produces a magnetic field $B_1$ at the centre. If the same wire is rewound into a coil of $3$ turns carrying the same current $I$,then the magnetic field at the centre $B_2$ is:

  • A
    $\frac{B_1}{9}$
  • B
    $9 B_1$
  • C
    $3 B_1$
  • D
    $\frac{B_1}{3}$

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