$A$ $100 mH$ coil carries a current of $1 A$. Energy stored in the form of magnetic field is (in $J$)

If the current in a coil is halved,then the energy stored becomes how many times the previous value?

$A$ current of $2\,A$ is increasing at a rate of $4\,A/s$ through a coil of inductance $2\,H$. The energy stored in the inductor per unit time is ... $J/s$.

Two circuits $A$ and $B$ are connected to identical d.c. sources each of e.m.f. $10 \ V$. Self-inductances of circuits $A$ and $B$ are respectively $L_A = 10 \ H$ and $L_B = 10 \ mH$. The total resistance of each circuit is $40 \ \Omega$. The ratio of energy consumed in circuit $A$ and circuit $B$ to build up the current to steady value is

The energy stored in a coil of inductance $L$ carrying a steady current $i$ is in the form:

$A$ current $2 \ A$ flows through a solenoid of self-inductance $3 \ mH$. The energy stored inside the solenoid is $.... \ mJ$.