$A$ long solenoid carrying current $I_1$ produces a magnetic field $B_1$ along its axis. If the current is reduced to $20 \%$ and the number of turns per $cm$ is increased five times,then the new magnetic field $B_2$ is equal to:

  • A
    $B_1$
  • B
    $\frac{B_1}{5}$
  • C
    $5 B_1$
  • D
    $0.25 B_1$

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