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(C) The given relation is $A = \frac{B^\alpha C^\beta}{D^\gamma E^\delta}$.According to the theory of propagation of errors,for a quantity $A = \frac{

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$(\alpha b + \beta c + \gamma d + \delta e) \%$

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(C) The given relation is $A = \frac{B^\alpha C^\beta}{D^\gamma E^\delta}$.According to the theory of propagation of errors,for a quantity $A = \frac{B^\alpha C^\beta}{D^\gamma E^\delta}$,the relative error is given by $\frac{\Delta A}{A} = \alpha \frac{\Delta B}{B} + \beta \frac{\Delta C}{C} + \gamma \frac{\Delta D}{D} + \delta \frac{\Delta E}{E}$.To find the maximum percentage error,we add the absolute values of the relative errors.Therefore,the maximum percentage error in $A$ is given by $\left( \frac{\Delta A}{A} 	imes 100 ight)_{max} = \alpha \left( \frac{\Delta B}{B} 	imes 100 ight) + \beta \left( \frac{\Delta C}{C} 	imes 100 ight) + \gamma \left( \frac{\Delta D}{D} 	imes 100 ight) + \delta \left( \frac{\Delta E}{E} 	imes 100 ight)$.Substituting the given percentage errors $b\%, c\%, d\%$ and $e\%$,we get the maximum percentage error as $(\alpha b + \beta c + \gamma d + \delta e) \%$.

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