A hemispherical portion of radius R is remove | vedclass

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(D) The force exerted by the liquid on the bottom surface of the cylinder is equal to the weight of the liquid displaced by the cylinder plus the forc

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$\rho g (V + \pi R^2 h)$

Vedclass · Answer

(D) The force exerted by the liquid on the bottom surface of the cylinder is equal to the weight of the liquid displaced by the cylinder plus the force due to the pressure at the depth of the cylinder's top surface.By Archimedes' principle,the buoyant force $F_B = ho V g$.The downward force due to the liquid column above the cylinder is $F_{top} = P_{top} 	imes A = (ho g h) 	imes (\pi R^2)$.The total upward force exerted by the liquid on the cylinder is $F_{net} = F_B + F_{top} = ho V g + ho g h \pi R^2$.Thus,the force on the bottom of the cylinder is $F_{bottom} = ho g (V + \pi R^2 h)$.

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