A horizontal pipeline carries water in a stre | vedclass

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(C) $1$. Using the equation of continuity, $A_1 v_1 = A_2 v_2$. Given $A_1 = 10 \,cm^2$, $v_1 = 1 \,m/s$, and $A_2 = 5 \,cm^2$. Thus, $10 	imes 1 = 5

Vedclass · Accepted Answer

$500$

Vedclass · Answer

(C) $1$. Using the equation of continuity, $A_1 v_1 = A_2 v_2$. Given $A_1 = 10 \,cm^2$, $v_1 = 1 \,m/s$, and $A_2 = 5 \,cm^2$. Thus, $10 	imes 1 = 5 	imes v_2$, which gives $v_2 = 2 \,m/s$.$2$. Since the pipeline is horizontal, the height $h_1 = h_2$. Applying Bernoulli's equation: $P_1 + \frac{1}{2} ho v_1^2 = P_2 + \frac{1}{2} ho v_2^2$.$3$. Substituting the values: $2000 + \frac{1}{2} 	imes 1000 	imes (1)^2 = P_2 + \frac{1}{2} 	imes 1000 	imes (2)^2$.$4$. $2000 + 500 = P_2 + 2000$.$5$. $2500 = P_2 + 2000$, so $P_2 = 500 \,Pa$.

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