$A$ big water drop is divided into $8$ equal droplets. $\Delta P_{S}$ and $\Delta P_{B}$ are the excess pressure inside a smaller and bigger drop respectively. The relation between $\Delta P_{S}$ and $\Delta P_{B}$ is

  • A
    $\Delta P_{B}=\Delta P_{S}$
  • B
    $\Delta P_{B}=\frac{1}{2} \Delta P_{S}$
  • C
    $\Delta P_{B}=\frac{1}{4} \Delta P_{S}$
  • D
    $\Delta P_{B}=2 \Delta P_{S}$

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