$A$ ball is released from the top of a tower of height $H \ m$. It takes $T \ s$ to reach the ground. The height of the ball from the ground after $\frac{T}{4} \ s$ is

  • A
    $\frac{13 H}{16}$
  • B
    $\frac{15 H}{16}$
  • C
    $\frac{11 H}{16}$
  • D
    $\frac{9 H}{16}$

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