$A$ student is throwing balls vertically upwards such that he throws the $2^{\text{nd}}$ ball when the $1^{\text{st}}$ ball reaches its maximum height. If he throws balls at an interval of $3 \ s$,what is the maximum height reached by the balls (in $m$)? (Take $g = 10 \ m/s^2$)
- A$45$
- B$35$
- C$25$
- D$30$
Explore More
Similar Questions
Galileo's law of odd numbers: "The distances traversed, during equal intervals of time, by a body falling from rest, stand to one another in the same ratio as the odd numbers beginning with unity [namely, $1: 3: 5: 7 \ldots$]". Prove it.
Medium
View Solution$A$ particle is dropped vertically from rest from a height. The time taken by it to fall through successive distances of $1\, m$ each will then be
Difficult
View Solution$A$ body is projected vertically upwards at time $t=0$ and it is seen at a height $H$ at times $t_1$ and $t_2$ seconds during its flight. The maximum height attained is ($g$ is acceleration due to gravity).
DifficultAP EAMCET 2009
View Solution$A$ bead is free to slide down a smooth wire tightly stretched between points $A$ and $B$ on a vertical circle. If the bead starts from rest at $A$,the highest point on the circle,
Medium
View Solution$A$ body thrown vertically upwards with an initial speed of $96\,ft/\sec$ reaches the ground after..........$sec$ $(g = 32\,ft/\sec^2)$.
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo