(D) In $U.C.M.$ (Uniform Circular Motion),the speed $V$ of the particle remains constant.Since the radius $R$ is also constant,the magnitude of angula

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(D) In $U.C.M.$ (Uniform Circular Motion),the speed $V$ of the particle remains constant.Since the radius $R$ is also constant,the magnitude of angular velocity $\omega = V/R$ remains constant.Angular acceleration $\alpha$ is defined as the rate of change of angular velocity,i.e.,$\alpha = d\omega/dt$.Since $\omega$ is constant,its derivative with respect to time is zero.Therefore,the angular acceleration of the particle is $0$.

Class 11 Physics 3-2.Motion in Plane Angular Variables and Basic of Uniform Circular Motion

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$A$ particle is moving in $U.C.M.$ with speed $V$ and radius $R$. The angular acceleration of the particle is

MHT CET 2022 All MHT CET

A
$V^2/R$ perpendicular to the plane of the circle.
B
$V^2/R$ along the tangent to the circle.
C
$V^2/R$ along the radius towards the centre of the circle.
D
zero.

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3-2.Motion in Plane

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Angular Variables and Basic of Uniform Circular Motion

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$A$ particle is moving in $U.C.M.$ with speed $V$ and radius $R$. The angular acceleration of the particle is

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