A man of mass M is standing on a platform. Th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The span of oscillation $L$ is the total distance between the extreme positions,which is equal to $2A$,where $A$ is the amplitude of oscillation.T

Vedclass · Accepted Answer

$2 \pi^{2} f^{2} L$

Vedclass · Answer

(D) The span of oscillation $L$ is the total distance between the extreme positions,which is equal to $2A$,where $A$ is the amplitude of oscillation.Therefore,$A = \frac{L}{2}$.The angular frequency $\omega$ is given by $\omega = 2 \pi f$.The acceleration $a$ of a particle in $S.H.M.$ is given by $a = -\omega^{2} x$.At the top of the oscillation (extreme position),the displacement $x = A = \frac{L}{2}$.Substituting the values,the magnitude of acceleration is $|a| = \omega^{2} A = (2 \pi f)^{2} 	imes \frac{L}{2}$.$|a| = 4 \pi^{2} f^{2} 	imes \frac{L}{2} = 2 \pi^{2} f^{2} L$.Thus,the correct option is $D$.

$A$ man of mass $M$ is standing on a platform. The platform is executing $S.H.M.$ of frequency $f$ in the vertical direction. The span of oscillation is $L$. What is the acceleration of the platform at the top of the oscillation?

Similar Questions

Two simple harmonic motions of angular frequency $300 \ rad/s$ and $3000 \ rad/s$ have the same amplitude. The ratio of their maximum accelerations is

Under the action of a force $F = -75 y$, where $F$ is in Newton and $y$ is in meters, an object of mass $3 \,kg$ executes simple harmonic motion. If the velocity of the object at the mean position is $2.5 \,ms^{-1}$, the maximum acceleration of the object is (in $\,ms^{-2}$)

$A$ particle of mass $10 \,g$ is undergoing $S.H.M.$ with an amplitude of $10 \,cm$ and a period of $0.1 \,s$. The maximum value of the force on the particle is about ............ $N$.

$A$ particle of mass $5 \,g$ is executing $S.H.M.$ with an amplitude $0.3 \,m$ and period $\frac{\pi}{5} \,s$. The maximum value of the force acting on the particle is (in $\,N$)

$A$ body of mass $0.4 \text{ kg}$ performs simple harmonic motion. It experiences a restoring force of $0.4 \text{ N}$ when its displacement from the mean position is $4 \text{ cm}$. The force constant and magnitude of acceleration respectively are

Vedclass Test Series

Exam Paper Generator

Online Exam Module