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(D) The time period of a simple pendulum is given by $T = 2\pi \sqrt{\frac{L}{g}}$,where $L$ is the distance between the point of suspension and the c

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first increases and then decreases,finally having the same value as at the beginning

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(D) The time period of a simple pendulum is given by $T = 2\pi \sqrt{\frac{L}{g}}$,where $L$ is the distance between the point of suspension and the center of gravity $(CG)$ of the bob.Initially,the $CG$ of the water-filled ball is at its geometric center.As water flows out through the small hole,the $CG$ of the remaining water shifts downwards,which increases the effective length $L$ of the pendulum,causing the time period $T$ to increase.As the ball becomes nearly empty,the $CG$ starts moving back up towards the geometric center of the ball.Consequently,the effective length $L$ decreases and returns to its original value.Therefore,the time period first increases and then decreases,finally returning to its initial value.

$A$ rubber ball filled with water,having a small hole,is used as the bob of a simple pendulum. The time period of such a pendulum

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