$A$ telescope has a large diameter of the objective. Then,its resolving power is

The diameter of the objective of the telescope is $0.1 \ m$ and the wavelength of light is $6000 \ \mathring{A}$. Its resolving power would be approximately:

The value of numerical aperture of the objective lens of a microscope is $1.25$. If light of wavelength $5000\,\mathring{A}$ is used, the minimum separation between two points, to be seen as distinct, will be....$\mu m$

If the aperture of a telescope is decreased,the resolving power will:

The resolving power of a telescope whose lens has a diameter of $1.22 \ m$ for a wavelength of $5000 \ \mathring{A}$ is

The angular resolution of a $10 \;cm$ diameter telescope at a wavelength of $5000 \;\mathring A$ is of the order of: