$A$ ray of light is incident at an angle of incidence '$i$' on one surface of a prism of small angle '$A$' and emerges normally from the other surface. If the refractive index of the material of the prism is '$\mu$',then the angle of incidence is equal to

$A$ light ray incident normally on one face of an equilateral prism and emerges out grazingly at the other face. The refractive index of the prism is

The angle of minimum deviation produced by a thin prism in air is $\delta_1$. What will be the minimum deviation $(\delta_2)$ if the prism is immersed in liquid? Given: refractive index of glass with respect to air $^a n_g = \frac{3}{2}$ and refractive index of liquid with respect to air $^a n_l = \frac{4}{3}$.

$A$ light ray is incident normally on one surface of an equilateral prism. The angle of deviation of the light ray is (refractive index of the material of the prism $=\sqrt{2}$) (in $^{\circ}$)

Consider the following statements for the refraction of light through a prism,when the angle of deviation is minimum.
$(A)$ The refracted ray inside the prism becomes parallel to the base.
$(B)$ Larger angle prisms provide smaller angle of minimum deviation.
$(C)$ The angle of incidence and the angle of emergence become equal.
$(D)$ There are always two sets of angles of incidence for which the deviation will be the same,except at the minimum deviation setting.
$(E)$ The angle of refraction becomes double the prism angle.
Choose the correct answer from the options given below.

$A$ thin prism having refracting angle $10^{\circ}$ is made of glass of refractive index $1.42$. This prism is combined with another thin prism of glass of refractive index $1.7$. This combination produces dispersion without deviation. The refracting angle of the second prism should be....$^{\circ}$