$A$ disc of mass $25 \ kg$ and radius $0.2 \ m$ is rotating at $240 \ r.p.m.$ $A$ retarding torque brings it to rest in $20 \ s$. If the torque is due to a force applied tangentially on the rim of the disc,then the magnitude of the force is:

  • A
    $\frac{\pi}{2} \ N$
  • B
    $2 \pi \ N$
  • C
    $\pi \ N$
  • D
    $4 \pi \ N$

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