$A$ transistor has a voltage gain '$A$'. If a fraction '$\beta$' of its output is fed back to the input of the transistor,then the transistor becomes an oscillator when:

In the circuit shown,the transistor used has a current gain $\beta = 100$. What should be the base resistor $R_B$ so that $V_{CE} = 5\,V$ and $V_{BE} = 0\,V$?

If $\alpha$ and $\beta$ are the current gains in the $CB$ and $CE$ configurations respectively of the transistor circuit,then $\frac{\beta - \alpha}{\alpha \beta} = $

In an experiment,the input characteristics are shown for a $CE$ configuration $n-p-n$ transistor for different output voltages. Based on the graph,which of the following is correct?

Consider an amplifier circuit in which a transistor is used in common-emitter mode. The load resistance is $3 k \Omega$. When a signal of $30 mV$ is added to the base-emitter voltage, the base current changes by $30 \mu A$ and the collector current changes by $3 mA$. The power gain in this circuit will be:

In a common emitter transistor amplifier, an input signal of $10 \ mV$ is applied. Due to this signal, the change in base current is $50 \ \mu A$ and the corresponding change in collector current is $5 \ mA$. If the load resistance in the collector-emitter circuit is $5 \ k\Omega$, the change in output voltage will be ..... $V$.